µ¥Ïàµç»úÊÇÒ»ÖÖ³£¼ûµÄµç¶¯»ú£¬ÆäÆ𶯵çÁ÷Êǵç»úÔËÐйý³ÌÖеÄÒ»¸öÖØÒª²ÎÊý¡£±¾ÎĽ«Îª¶ÁÕßÏêϸ½éÉܵ¥Ïàµç»úÆ𶯵çÁ÷µÄ¼ÆËã·½·¨£¬°üÀ¨¹«Ê½ÍƵ¼ºÍʵ¼ÊÓ¦Óá£

1. µ¥Ïàµç»úÆ𶯵çÁ÷µÄ¶¨Òå
µ¥Ïàµç»úÆ𶯵çÁ÷ÊÇÖ¸µç»úÔÚÆô¶¯¹ý³ÌÖÐËùÐèÒªµÄµçÁ÷Öµ¡£ÔÚµç»úÆô¶¯Ê±£¬ÓÉÓÚת×ӵĹßÐÔ×÷Óú͵ç»úÄÚ²¿µç×èµÄÓ°Ï죬µç»úÆô¶¯Ê±ÐèÒªÏûºÄ±ÈÔËÐÐʱ¸ü´óµÄµçÁ÷¡£Òò´Ë£¬µ¥Ïàµç»úÆ𶯵çÁ÷Êǵç»úÉè¼ÆºÍʹÓùý³ÌÖÐÐèÒªÖص㿼ÂǵIJÎÊýÖ®Ò»¡£
2. µ¥Ïàµç»úÆ𶯵çÁ÷µÄ¼ÆËã·½·¨
µ¥Ïàµç»úÆ𶯵çÁ÷µÄ¼ÆËã·½·¨¿ÉÒÔͨ¹ýÅ·Ä·¶¨Âɺ͵ç»úµÄµÈЧµç·ģÐÍÀ´ÍƵ¼¡£¾ßÌå¶øÑÔ£¬¿ÉÒÔ²ÉÓÃÒÔϹ«Ê½
I = (U - E) / R
ÆäÖУ¬I±íʾµçÁ÷£¬U±íʾµçÔ´µçѹ£¬E±íʾµç»úµÄ·´µç¶¯ÊÆ£¬R±íʾµç»úµÄµç×è¡£
ÔÚµ¥Ïàµç»úÆô¶¯¹ý³ÌÖУ¬×ª×ӵĹßÐÔ×÷ÓûᵼÖµç»úÄÚ²¿µÄ·´µç¶¯ÊÆE½ÏС£¬Òò´ËÆ𶯵çÁ÷»á±ÈÔËÐÐʱµçÁ÷´óºÜ¶à¡£¸ù¾Ýµç»úµÄµÈЧµç·ģÐÍ£¬¿ÉÒÔ½«µç»úµÄµç×èR±íʾΪ
R = R1 + R2
ÆäÖУ¬R1±íʾµç»úµÄ¶¨×Óµç×裬R2±íʾµç»úµÄת×Óµç×è¡£ÔÚµ¥Ïàµç»úÆô¶¯¹ý³ÌÖУ¬×ª×Óµç×èR2ºÜС£¬¿ÉÒÔºöÂÔ²»¼Æ¡£Òò´Ë£¬µç»úµÄµç×èR¿ÉÒÔ½üËÆΪ¶¨×Óµç×èR1¡£
3. µ¥Ïàµç»úÆ𶯵çÁ÷µÄʵ¼ÊÓ¦ÓÃ
µ¥Ïàµç»úÆ𶯵çÁ÷µÄ¼ÆËã·½·¨¿ÉÒÔÓ¦ÓÃÓÚµç»úµÄÉè¼Æ¡¢Ñ¡ÐͺÍʹÓùý³ÌÖС£ÔÚµç»úµÄÉè¼ÆºÍÑ¡Ð͹ý³ÌÖУ¬ÐèÒª¸ù¾Ýʵ¼ÊʹÓó¡¾°ºÍ¸ºÔØÌØÐÔÀ´È·¶¨µç»úµÄ¶î¶¨µçѹºÍµçÁ÷¡£ÔÚµç»úµÄʹÓùý³ÌÖУ¬ÐèҪעÒâµç»úÆð¶¯Ê±µÄµçÁ÷´óС£¬ÒÔ±ÜÃâ¶ÔµçÔ´ºÍµç»ú±¾ÉíÔì³ÉË𺦡£
×ÜÖ®£¬µ¥Ïàµç»úÆ𶯵çÁ÷µÄ¼ÆËã·½·¨Êǵç»úÉè¼ÆºÍʹÓùý³ÌÖеÄÖØÒªÄÚÈÝ¡£Í¨¹ý±¾ÎĵĽéÉÜ£¬¶ÁÕß¿ÉÒÔ¸ü¼ÓÉîÈëµØÁ˽ⵥÏàµç»úÆ𶯵çÁ÷µÄÏà¹Ø֪ʶ£¬Îªµç»úµÄÉè¼ÆºÍʹÓÃÌṩÓмÛÖµµÄ²Î¿¼¡£